n+1+(n*0.5)+[37-(2n-4)]=5.50

Solution for n+1+(n*0.5)+[37-(2n-4)]=5.50 equation:

Simplifying
n + 1 + (n * 0.5) + [37 + -1(2n + -4)] = 5.50

Reorder the terms for easier multiplication:
n + 1 + (0.5n) + [37 + -1(2n + -4)] = 5.50

Reorder the terms:
n + 1 + (0.5n) + [37 + -1(-4 + 2n)] = 5.50
n + 1 + (0.5n) + [37 + (-4 * -1 + 2n * -1)] = 5.50
n + 1 + (0.5n) + [37 + (4 + -2n)] = 5.50

Combine like terms: 37 + 4 = 41
n + 1 + (0.5n) + [41 + -2n] = 5.50

Remove brackets around [41 + -2n]
n + 1 + (0.5n) + 41 + -2n = 5.50

Reorder the terms:
1 + 41 + n + (0.5n) + -2n = 5.50

Combine like terms: 1 + 41 = 42
42 + n + (0.5n) + -2n = 5.50

Combine like terms: n + (0.5n) = 1.5n
42 + 1.5n + -2n = 5.50

Combine like terms: 1.5n + -2n = -0.5n
42 + -0.5n = 5.50

Solving
42 + -0.5n = 5.50

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-42' to each side of the equation.
42 + -42 + -0.5n = 5.50 + -42

Combine like terms: 42 + -42 = 0
0 + -0.5n = 5.50 + -42
-0.5n = 5.50 + -42

Combine like terms: 5.50 + -42 = -36.5
-0.5n = -36.5

Divide each side by '-0.5'.
n = 73

Simplifying
n = 73